12(x+3)(x-2)=3(4x^2+11x+7)-10

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Solution for 12(x+3)(x-2)=3(4x^2+11x+7)-10 equation: 



12(x+3)(x-2)=3(4x^2+11x+7)-10

We move all terms to the left:

12(x+3)(x-2)-(3(4x^2+11x+7)-10)=0

We multiply parentheses ..

12(+x^2-2x+3x-6)-(3(4x^2+11x+7)-10)=0



We calculate terms in parentheses: -(3(4x^2+11x+7)-10), so:

3(4x^2+11x+7)-10

We multiply parentheses

12x^2+33x+21-10

We add all the numbers together, and all the variables

12x^2+33x+11

Back to the equation:

-(12x^2+33x+11)



We multiply parentheses

12x^2-24x+36x-(12x^2+33x+11)-72=0

We get rid of parentheses

12x^2-12x^2-24x+36x-33x-11-72=0

We add all the numbers together, and all the variables

-21x-83=0

We move all terms containing x to the left, all other terms to the right

-21x=83

x=83/-21

x=-3+20/21

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